Function isSliceOf
Determines whether needle is a slice of haystack.
bool isSliceOf(T1, T2)(
scope const(T1)[] needle,
scope const(T2)[] haystack
) pure nothrow @nogc @trusted;
History
Added on February 11, 2025.
Example
string s0 = "01234";
const(char)[] s1 = s0[1 .. $];
const(void)[] s2 = s1 .castTo!(const(void)[]);
string s3 = s1 .idup;
assert( s0 .isSliceOf(s0));
assert( s1 .isSliceOf(s0));
assert( s2 .isSliceOf(s0));
assert(!s3 .isSliceOf(s0));
assert(!s0 .isSliceOf(s1));
assert( s1 .isSliceOf(s1));
assert( s2 .isSliceOf(s1));
assert(!s3 .isSliceOf(s1));
assert(!s0 .isSliceOf(s2));
assert( s1 .isSliceOf(s2));
assert( s2 .isSliceOf(s2));
assert(!s3 .isSliceOf(s2));
assert(!s0 .isSliceOf(s3));
assert(!s1 .isSliceOf(s3));
assert(!s2 .isSliceOf(s3));
assert( s3 .isSliceOf(s3));
assert(s1 .length == 4);
assert(s1[0 .. 0] .isSliceOf(s1));
assert(s1[0 .. 1] .isSliceOf(s1));
assert(s1[1 .. 2] .isSliceOf(s1));
assert(s1[1 .. 3] .isSliceOf(s1));
assert(s1[1 .. $] .isSliceOf(s1));
assert(s1[$ .. $] .isSliceOf(s1));